本篇文章為大家展示了為什么uint8_t 類型變量無利用c++進行打印，內容簡明扼要并且容易理解，絕對能使你眼前一亮，通過這篇文章的詳細介紹希望你能有所收獲。

將uint8_t 轉化為unsigned 類型

使用一元運算符+(和- 運算符對應)

測試代碼如下

#include 
#include 
#include 
int main()
{
 std::uint8_t uint8_num = 10;
 std::cout << "uint8_t num is " << uint8_num << std::endl; //無法打印
 std::cout << "after cast to unsigned, uint8_t num is " << unsigned(uint8_num) << std::endl; //能正常打印
 std::cout << "with a unary + operator, uint8_t num is " << +uint8_num << std::endl; //能正常打印
 std::cout << "type of '+uint8_num' is " << typeid(+uint8_num).name() << std::endl;
 return 0;
}